[boost] Re: shared_ptr: operator<

From: Braden N. McDaniel (braden_at_[hidden])
Date: 2000-02-27 18:47:54

On Sun, 27 Feb 2000, Kevlin Henney wrote:

> "For templates greater, less, greater_equal, and less_equal, the
> specializations for any pointer type yield a total order, even if the
> built-in operators <, >, <=, >= do not." [20.3.3 para 8]

Okay, silly question time: What exactly is meant here by the term "total
order"?

-- 
Braden N. McDaniel
braden_at_[hidden]
<URL:http://www.endoframe.com>