Re: [boost] Re: Re: Dimensional Analysis Interest?

From: Jan Van Dijk (janvandijkinjapan_at_[hidden])
Date: 2003-10-17 07:29:17

On Thursday 16 October 2003 21:38, Jeff Flinn wrote:
> "Jan Van Dijk" <janvandijkinjapan_at_[hidden]> wrote in message
> news:200310170421.57569.janvandijkinjapan_at_yahoo.co.jp...
>
[...]
> > Unfortunately the algebra (the transformation properties) is not linear.
>
> Just
>
> > consider conversion from the temperature-'base vector' K (kelvin) to C
> > (Celsius), C=K-273.15.
>
> Looks perfectly linear to me?  y = mx + b => C = (1)K - 273.15

In linear algebra (the context of Deane's) mail the word 'linear' has a 
diferent meaning. An operator L is linear in its argument iff

        L(ax+by)=aL(x)+bL(y)

For starters this implies that L(0)=0 (just take a=b=0). Obviously this is not 
true for the operator L(T)=T-273.15, the transformation from K to C.

        Bye, Jan.

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