Re: [boost] [function types] New tag type logic [update2]

From: Rob Stewart (stewart_at_[hidden])
Date: 2005-07-07 16:57:00

From: Tobias Schwinger <tschwinger_at_[hidden]>
> Rob Stewart wrote:
> > From: Tobias Schwinger <tschwinger_at_[hidden]>
> >>Rob Stewart wrote:
> >>
> > Note that a function type can be decorated--to use your term--to
> > *form* a pointer to function, for example.
> 
> Being picky I guess you meant "a pointer to function *type*" - otherwise "form" 
> should be "declare" ;-).

Indeed.

>     ...and other compound types, such as function pointer, function reference and
>     member function types.
> 
> I believe I can get rid of that term in the rest of the text as well.

Cool.

> > I think I see what you're trying to say.  Perhaps the right
> > wording is that "a default value is used for a missing property
> > when synthesizing a type," or something along those lines.
> 
> Something along those lines. How's
> 
>     Default values are selected for properties not specified by the tag here (see
>     <somewhere else>).
> 
> ?

Oh, sorry.  I guess I missed replying to that.  I like "are
selected," particularly if you avoid the passive voice.  That is,
say what is doing the selecting.

> > I see.  How about, "creates the type of an undecorated function
> > (variadic in this case) of the default...."
> 
> OK. Let's get rid of the "decorate" artefact:
> 
>     ...creates the type of a function (variadic in this case) of the default...

Good.

-- 
Rob Stewart                           stewart_at_[hidden]
Software Engineer                     http://www.sig.com
Susquehanna International Group, LLP  using std::disclaimer;