Re: [boost] [Serialization] why operator &()?

From: Jim Hyslop (jhyslop_at_[hidden])
Date: 2005-10-14 15:18:52

David Abrahams wrote:
> Jim Hyslop <jhyslop_at_[hidden]> writes:

>>Except that operator precedence only applies to "built-in" operators - user
>>defined operators are function calls, and have that level of precedence.
> 
> 
> No, that's wrong.

You are correct, of course. 13.5 paragraph 6 states it quite clearly: 
"It is not possible to change the precedence, grouping, or number of 
operands of operators." My apologies for the inaccuracy.

-- 
Jim