Re: [boost] Problem with range?

From: Neal Becker (ndbecker2_at_[hidden])
Date: 2006-05-30 10:51:28

Thorsten Ottosen wrote:

> Neal Becker wrote:
>> STL iterators are designed so that ordinary pointers can be iterators. 
>> Can we do the same with boost::range?
>> 
>> With STL we can do:
>> int x;
>> std::copy (&x, &x+1, output);
>> 
>> Does this work for range?
>> 
>> #include <boost/range.hpp>
>> 
>> template<typename in_t>
>> void F (in_t const& in) {
>>   typename boost::range_const_iterator<in_t>::type i = boost::begin (in);
>>   for (; i != boost::end (in); ++i) ;
>> }
>> 
>> int main() {
>>   int x;
>>   F (boost::sub_range<int*> (&x, &x+1));
>> }
>> 
>> usr/local/src/boost.cvs/boost/range/sub_range.hpp:26:   instantiated from
>> ‘boost::sub_range<int*>’
>> test.cc:11:   instantiated from here
>> /usr/local/src/boost.cvs/boost/range/mutable_iterator.hpp:37: error:
>> ‘int*’ is not a class, struct, or union type
>> 
>> How do I turn the 'int x' into a 'range'?
> 
> That is certainly an interesting question. By default, T* is not a
> Range. It's an iterator:
> 
> int x;
> F( make_iterator_range(&x, &x+1) );
> 
> -Thorsten

Oh yes, thanks, that's what I wanted.