Re: [boost] [proto] transform for flattening an expression - how?

From: Markus Werle (numerical.simulation_at_[hidden])
Date: 2008-03-18 04:06:41

Eric Niebler <eric <at> boost-consulting.com> writes:

> This one is easy:
> 
>      proto::unpack_expr<sum>(
>          fusion::as_vector(
>              proto::flatten(a + b + c + d)
>          )
>      );
> 
> fusion::as_vector() is needed because proto::unpack_expr() currently 
> requires a random access sequence, and proto::flatten() returns a 
> forward sequence. I should loosen that requirement.

This means an interface change. 
Can we have your word on that it will be changed before official release?

Markus