Re: [boost] Giving names to formal parameters of lambda expressions: a named placeholder trick.

From: shunsuke (pstade.mb_at_[hidden])
Date: 2008-04-02 17:59:48

Giovanni Piero Deretta wrote:
> Hum, if you want to have guaranteed static initialization, you need to
> statically know the function pointer value:
> 
> template<typename Sig, Sig * p>
> static_function_ptr  {
>    typedef typename result_of_sig<Sig>::type result_type;
> 
>    template<typename Args...>
>    result_type operator()(Args.... args) {
>        return p(args);
>    }
> };
> 
> Substitute the pseudo-variadic syntax with proper preprocessor magic :).

Egg secretly has the feature.
See "egg/inlined.hpp".

>>  I'm really afraid that those macros may keep users away from the library.
>>
> 
> Hey, maybe it is just me, maybe others won't have any problems with
> them. I just find the macro based initialization ugly and unnecessary
> complex.

You expect something like this?:

static_result_of<T_curry2(F)>::type c = BOOST_EGG_CURRY2({}); // static
boost::result_of<T_curry2(F const &)>::type c = curry2(f); // dynamic
stateless_result_of<T_curry2(F)>::type c = BOOST_EGG_STATELESS(); // for stateless one.

Regards,

-- 
Shunsuke Sogame