Re: [boost] [Serialization] this seems wrong

Subject: Re: [boost] [Serialization] this seems wrong
From: Kenny Riddile (kfriddile_at_[hidden])
Date: 2008-12-02 14:43:15

Michael Marcin wrote:
> Michael Marcin wrote:
>> Michael Marcin wrote:
>>> I don't know about getting rid of the unnamed namespace but 
>>> essentially we just need a unique name per type in a translation 
>>> unit.. so how about:
>>>
>>> #define BOOST_CLASS_EXPORT_GUID(T, K)                                \
>>> namespace                                                            \
>>> {                                                                    \
>>>     template< typename U >                                           \
>>>     class init_guid                                                  \
>>>     {                                                                \
>>>         static ::boost::archive::detail::guid_initializer<U> const & \
>>>         guid_initializer_;                                           \
>>>     };                                                               \
>>>     template<> ::boost::archive::detail::guid_initializer<T> const & \
>>>         init_guid<T>::guid_initializer_ =                            \
>>>             ::boost::serialization::singleton<                       \
>>>                 ::boost::archive::detail::guid_initializer<T>        \
>>>             >::get_mutable_instance().export_guid(K);                \
>>> }
>>>
>>
>> Do we still need to explicitly instantiate init_guid here? If so add
>>
>> template class init_guid<T>;
>>
> 
> Never mind this fails if we have 2 export macros.. silly me.
> 
I'm thinking I may just call BOOST_CLASS_EXPORT_GUID directly instead of 
BOOST_CLASS_EXPORT to get around this problem.