Re: [boost] [move] auto-generated operator=

Subject: Re: [boost] [move] auto-generated operator=
From: David Abrahams (dave_at_[hidden])
Date: 2009-11-16 21:35:42

on Mon Nov 16 2009, Ion Gaztañaga <igaztanaga-AT-gmail.com> wrote:

> David Abrahams escribió:
>> On Nov 16, 2009, at 7:46 AM, David Abrahams wrote:
> m with requiring move-enablers to supply a swap.
>>
>> In fact, I don't even think we need to do that.  This seems to work pretty well:
>>
>> #define BOOST_COPYABLE_AND_MOVABLE(TYPE)\
>>    public:\
>>    TYPE& operator=(TYPE t)\
>>    { return this->operator=(static_cast< ::boost::rv<TYPE>&>(t)); }  \
>> //
>
> Interesting. This works for some types but it has performance impact in types
> like vector because they can't reuse previous allocated resource
> (e.g. capacity).

Yeah, but I think it might be worth the cost.  Otherwise you end up with
a world where movable types in libraries are poison because, e.g., they
are incompatible with std containers.

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