Re: dynamic_*<T>

From: Glen Fernandes (glen.fernandes_at_[hidden])
Date: 2020-01-24 16:10:01

Alexander wrote:
> So if T[] and T[N] are valid, then T[N][M] should also be. This increases
the scope greatly but has an incredible difficult questions to answer: What
would operator[] return? I don't have a good answer...

Simple questions that already have an answer:
The same way shared_ptr<T[N][M]> works today. :)

Its operator[] returns element_type&

So:
     auto p = allocate_shared<int[5][1024]>(alloc);
     p[3][675] = 8;

     auto q = allocate_unique<double[][2][3][4]>(alloc, size);
     q[index][1][1][1] = 0.95;

Then:
    dynamic<int[5][1024], Allocator> a(alloc);
    a[3][675] = 8;

i.e. Making it work for T[N] also automatically makes it work for T[N][M].

Glen