Re: [ublas] (no subject)

From: Brad Bell (bradbell_at_[hidden])
Date: 2006-06-01 16:36:47

It appears to me that you should use
        vector<float> new_vec( vec.size() );

On Tue, 30 May 2006, dvir schirman wrote:

> Hi
>
> I want to declare a new vector "new_vec" at the same size as an existing
> vector "vec".
> I tried to use:
>
> vector<float> new_vec(vec.size);
>
> but I got the following error:
>
> test_b3.cpp:19: error: no matching function for call to
> `boost::numeric::ublas::vector<float,
> boost::numeric::ublas::unbounded_array<float, std::allocator<float> >
> >::vector(<unknown type>)'
> ../boost/boost/numeric/ublas/vector.hpp:66: note: candidates are:
> boost::numeric::ublas::vector<T, A>::vector(const
> boost::numeric::ublas::vector<T, A>&) [with T = float, A =
> boost::numeric::ublas::unbounded_array<float, std::allocator<float> >]
> ../boost/boost/numeric/ublas/vector.hpp:62: note:
> boost::numeric::ublas::vector<T, A>::vector(typename A::size_type, const A&)
> [with T = float, A = boost::numeric::ublas::unbounded_array<float,
> std::allocator<float> >]
> ../boost/boost/numeric/ublas/vector.hpp:57: note:
> boost::numeric::ublas::vector<T, A>::vector(typename A::size_type) [with T =
> float, A = boost::numeric::ublas::unbounded_array<float,
> std::allocator<float> >]
> ../boost/boost/numeric/ublas/vector.hpp:53: note:
> boost::numeric::ublas::vector<T, A>::vector() [with T = float, A =
> boost::numeric::ublas::unbounded_array<float, std::allocator<float> >]
>
> Thanks for your help.
>
> Dvir.
>