Hi all,<br><br>In my post &quot;How to use function calls in ublas expression&quot; [1] I was redirected to [2] which was very useful.<br><br>Now I can write code like this withput creating unnecessary temporaries<br><br>ublas::vector&lt;double&gt; x, y, z, w;<br>
x = y + ublas::apply_to_all( z, functor::log&lt;double&gt;() ) + w;<br><br>But after looking into ublas code I found out that the template machinery ends up calling the static function apply() of the functor, making it impossible to use stateful functors in the expressions.<br>
<br>My question is: does anyone know the rationale for this decision? I would expect that allowing stateful functors and calling their operator() member function (like in STL) would make ublas much more extendable.<br><br>
Thanks!<br><br>[1] <a href="http://boost.2283326.n4.nabble.com/Boost-ublas-How-to-use-function-calls-in-ublas-expression-tt2711515.html#a2711519">http://boost.2283326.n4.nabble.com/Boost-ublas-How-to-use-function-calls-in-ublas-expression-tt2711515.html#a2711519</a><br>
<br>[2] <a href="http://www.crystalclearsoftware.com/cgi-bin/boost_wiki/wiki.pl?Examples_-_How_To_Extend_UBLAS">http://www.crystalclearsoftware.com/cgi-bin/boost_wiki/wiki.pl?Examples_-_How_To_Extend_UBLAS</a><br><br>