What is the most efficient way to convert Fortran’s column array access like shown below to C++?

a(i,:) = 0 ! set entire column to zero

I suspect best solution might use matrix proxies like matrix_row?

Can this be done on one line without the for loop?

Can you help me fix the syntax on the commented out code that attempted to use iterators?

#include "boost/numeric/ublas/matrix.hpp"

#include "boost/numeric/ublas/matrix_proxy.hpp"

#include "boost/numeric/ublas/io.hpp"

int main()

{

const int N = 3;

   boost::numeric::ublas::matrix<double> M(N,N,1.0);

   boost::numeric::ublas::matrix_row<boost::numeric::ublas::matrix<double> > row1(M,1);

//??std::vector<boost::numeric::ublas::matrix<double>*>::iterator mit;

//??how to set the matrix row to zero on one line like Fortran 90 a(1,:)=0.0

//for (mit = row1.begin(); mit != row1.end(); ++mit)

//for_each(row1.begin(), row1.end(), [] (const std::unique_ptr<??>& ptr)

for (int i = 0; i < row1.size(); ++i) // not i++

      row1(i) = 0.0;

   std::cout << "row = " << row1 << std::endl;

   std::cout << "Matrix = " << M << std::endl;

return N;

}