Re: [Boost-build] Merging files (same type for input and output)

Subject: Re: [Boost-build] Merging files (same type for input and output)
From: Ian Emmons (ian_at_[hidden])
Date: 2013-09-03 10:27:52

import common ;

...

make «target-file-path» : «source-file-path» : @common.copy ;

On Sep 2, 2013, at 3:36 AM, Mike Gresens <mgresens_at_[hidden]> wrote:
> Thank you, Ian!
> 
> Your suggestion sounds good :-)
> I am not sure how to rename/copy files - but I will try!
> 
> Best regards,
> Mike...
> 
> Am 29.08.2013 um 18:24 schrieb Ian Emmons <ian_at_[hidden]>:
> 
>> Mike,
>> 
>> Can you create the following generators:
>> 
>> 1. .r to .rsrc-xyzzy
>> 2. .fr to .rsrc-xyzzy
>> 3. .rsrc-xyzzy to .rsrc
>> 
>> where #3 merges all its dependents into one .rsrc output.  Then make sure that if #3 has only one dependent, it will simply copy the input to output.  Then you just create the following targets:
>> 
>> result.rsrc with dependents foo.rsrc-xyzzy and bar.rsrc-xyzzy
>> foo.rsrc with dependent foo.rsrc-xyzzy
>> bar.rsrc with dependent bar.rsrc-xyzzy
>> 
>> Does that sound workable?
>> 
>> -Ian
>> 
>> 
>> On Aug 29, 2013, at 7:29 AM, Mike Gresens <mgresens_at_[hidden]> wrote:
>>> Hi there,
>>> 
>>> i am trying to do something like that:
>>> 
>>> 1) Generate foo.rsrc from foo.r
>>> 2) Generate bar.rsrc from bar.fr
>>> 3) Merge foo.rsrc and bar.rsrc into result.rsrc
>>> 
>>> Steps 1 and 2 are done. I have now generators for that.
>>> But how can i merge the files? The types for input and output are the same…
>>> PS: I need the files foo.rsrc and bar.rsrc too. So i can't rename their type to something else...
>>> 
>>> Thank you,
>>> Mike...
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