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From: Caleb Epstein (caleb.epstein_at_[hidden])
Date: 2005-11-17 13:24:55


On 11/17/05, Kevin Wheatley <hxpro_at_[hidden]> wrote:

> don't know of a great solution but under IEEE class floats can't you
> compute the numbers...
>
> NaN = 0/0
> +inf = +1/0
> -inf = -1/0
> +0 = 0/+1
> -0 = 0/-1
> etc.

The +/-0 formulas work, but not the NaN and +/-Inf ones (divide by zero
generates a floating point exception). Thankfully, can't we use
numeric_limits for some of these?

std::numeric_limits<T>::infinity()
std::numeric_limits<T>::quiet_NaN()
std::numeric_limits<T>::signaling_NaN()
std::numeric_limits<T>::denorm_min()

--
Caleb Epstein
caleb dot epstein at gmail dot com


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