The problem is given something like +/inf how do I create a float with that value? 
 
Can I use something like this?
 
double x;
x = std::numeric_limits<T>::quiet_NaN();
 
assert(x == std::numeric_limits<T>::quiet_NaN());
 
Robert Ramey
 
 
"Caleb Epstein" <caleb.epstein@gmail.com> wrote in message news:989aceac0511171024g42ca640dvff8257333577e6e2@mail.gmail.com...
On 11/17/05, Kevin Wheatley <hxpro@cinesite.co.uk> wrote:

don't know of a great solution but under IEEE class floats can't you
compute the numbers...

NaN = 0/0
+inf = +1/0
-inf = -1/0
+0 = 0/+1
-0 = 0/-1
etc.

The +/-0 formulas work, but not the NaN and +/-Inf ones (divide by zero generates a floating point exception).  Thankfully, can't we use numeric_limits for some of these?

std::numeric_limits<T>::infinity()
std::numeric_limits<T>::quiet_NaN()
std::numeric_limits<T>::signaling_NaN()
std::numeric_limits<T>::denorm_min()

--
Caleb Epstein
caleb dot epstein at gmail dot com

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