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From: Oliver.Kowalke_at_[hidden]
Date: 2006-05-03 01:55:53


Hmm - I would use boost::function instead of declaring a
function-pointer object by myself.
Regards,
Oliver

>On 5/2/06, Oliver.Kowalke_at_[hidden] <Oliver.Kowalke_at_[hidden]>
wrote:
>> how can I define a function<> object which returns a value of
>> the same type:
>
>This was taken from GotW article 57:
>http://www.gotw.ca/gotw//057.htm
>
> struct FuncPtr_;
> typedef FuncPtr_ (*FuncPtr)();
>
> struct FuncPtr_
> {
> FuncPtr_( FuncPtr pp ) : p( pp ) { }
> operator FuncPtr() { return p; }
> FuncPtr p;
> };
>
>Now we can declare, define, and use f() naturally:
>
> FuncPtr_ f() { return f; } // natural return syntax
>
> int main()
> {
> FuncPtr p = f(); // natural usage syntax
> p();
> }
>
>HTH,
>
>Michael Fawcett
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