[Boost-users] [function_types] Removing class type from member function signature.

From: Fabio Fracassi (f.fracassi_at_[hidden])
Date: 2008-08-18 08:16:48

Hi,

I'm currently trying to wrap (or forward) a call to 
boost::signal<A_func_Signature>::connect(), to - amongst other things - 
insulate users from using boost::bind.

So what I have is something like this:

template< typename Signature, class Reciever >
void connect( const signal_id& id,
              const Signature& sig,
                const Reciever* rcv
              )
{
        typedef ???? AdaptedSignature;

        get_signal< AdaptedSignature > ( id ) -> connect(boost::bind(sig, rcv, 
_1));
}

now this code is supposed to be called like this:

connect( some_signal_id, &SomeClass::some_member, someClass_instance );

where SomeClass::some_member has the same function signature as the 
signal which is associated with some_signal_id.

e.g.

boost::signal<void (bool)> signal;

struct SomeClass {
        void some_member(bool b);
};

So my question is how can I construct the "AdaptedSignature" type from 
the template deduced "Signature"?
 From what I gather from the documentation, boost function_types might 
hold the answer to my question, but I cannot figure out how.
So is what I am trying to do possible, and is function_types the right tool?

TIA

Fabio