[Boost-users] [enable_if] Doesn't work for static member functions ?

Subject: [Boost-users] [enable_if] Doesn't work for static member functions ?
From: Jean-Louis Leroy (jl_at_[hidden])
Date: 2009-09-23 16:54:42

Consider :

template<typename U>
struct Test {
   template<typename T>
   typename enable_if<is_same<T, int>, void>::type test() {
     cout << "int" << endl;
   }

   template<typename T>
   typename enable_if<is_same<T, char>, void>::type test() {
     cout << "char" << endl;
   }
};

template<typename T>
typename enable_if<is_same<T, int>, void>::type test() {
   cout << "int" << endl;
}

template<typename T>
typename enable_if<is_same<T, char>, void>::type test() {
   cout << "char" << endl;
}

int _tmain(int argc, _TCHAR* argv[])
{
   test<int>();
   test<char>();
   Test<int>::test<double>(); // error
   return 0;
}

MSVC9 will give a compilation error (see below) where marked. Am I 
missing something obvious ?

Thanks,
J-L

1>c:\users\jll\documents\visual studio 
2008\projects\boost_1_40_0\libs\rdb\test\test.cpp(325) : error C2143: 
syntax error : missing ';' before '<'
1>        c:\users\jll\documents\visual studio 
2008\projects\boost_1_40_0\libs\rdb\test\test.cpp(333) : see reference 
to class template instantiation 'Test<U>' being compiled
1>c:\users\jll\documents\visual studio 
2008\projects\boost_1_40_0\libs\rdb\test\test.cpp(325) : error C4430: 
missing type specifier - int assumed. Note: C++ does not support default-int
etc etc etc