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Subject: Re: [Boost-users] Several novice questions concerning threading
From: Master (master.huricane_at_[hidden])
Date: 2012-04-11 15:09:20


thank you very much for all the info . i really do appreciate it :)
have look at this link please :
http://docs.wxwidgets.org/trunk/classwx_thread.html
these are some of the features i would like to have , when using boost .
unfortunately i think boost threading has yet to be complete , specially
for being used by the novices like me ,.
those managements are really hard , and i wanted to use boost to avoid
digging into any os realtaed apis myself :( it seems i need to get all i
need from the Os API .
i have a C#.net back ground , working with threads in c# was indeed simple
, but this much complexity and chores of management to be done is really
alot for me .
i need to re organize my thoughts on how i should go about it .
if only i had examples showing the real world problems and issues using
threads , i would be fine .
any way about the program and why i tried mixing the stuff : have look at
here please : http://en.highscore.de/cpp/boost/ the exercise section ,
i was asked to speed things up , and there i said to myself , imagine that
you faced a situation in which you couldnt simply separate the critical
region , so i tried to teach myself the ways of coping such situations .
again i imagined a situation in which there are couple of reader threads
reading a buffer output and simultaneously a writer thread is to write sth
on the buffer , there i though if priority of threads .
again i imagined a situation in which there are several inputs ( messages )
which need to be decoded and then taken care of , and then i needed to make
sure that those messages are delivered sucessfully or their respective goal
are carried out . thats where i tried to know sth about thread status to
check about their success of failure .
and about the sequential execution i should say that , thats because i
imagined a situation where there are two groups of threads , one doing the
reading chores and the other one doing the writing chores ,
i wanted to make sure that no reader proceeds a writer thread , so that it
avoids any failure .

again thank you for your time :)

On Wed, Apr 11, 2012 at 10:05 PM, Ovanes Markarian
<om_boost_at_[hidden]>wrote:

>
>
> On Wed, Apr 11, 2012 at 6:39 PM, Master <master.huricane_at_[hidden]> wrote:
>
>> Thank you very much :)
>> for keeping track of my created threads i decided to use thread_groups
>> and accumulate them there . i came up with sth like this :
>>
>> boost::thread_group threadstore;
>>
>> threadstore.add_thread(&thread);
>> threadstore.add_thread(&thread2);
>> BOOST_FOREACH(boost::thread t ,threadstore.threads)
>> {
>> cout<<t.get_id();
>> }
>>
>> As far as I can see the docs thread_group (
> http://www.boost.org/doc/libs/1_49_0/doc/html/thread/thread_management.html#thread.thread_management.threadgroup) does
> not expose the public member threads. Even if it is there, it is an
> implementation detail, which can change/(made private) with any release of
> boost and your code will break. I suggest you to implement an approache
> suggested by Vicente.
>
>
>> well it didnt compiled ! before that , i tried using sth like this which
>> failed nontheless .
>>
>> vector<boost::thread> threadstore;
>>
>> threadstore.push_back(thread);
>> threadstore.push_back(thread2);
>> BOOST_FOREACH(boost::thread t ,threadstore)
>> {
>> cout<<t.get_id();
>> }
>>
>> Thread group is just a management construct, it does not allow you to
> iterate over the threads. BOOST_FOREACH supports STL like container.
> thread_group does not provide begin/end iterators.
>
>
>>
>> im clueless of the cause .
>> The threadstore has member called :threads , which i dont know how to
>> work around it , there is also another member named: m ,
>> which i have no clue of what it is !nor i know where it came form! or
>> what i can do with it!
>>
> i couldnt find any information on these members on the boost::thread
>> documentation either
>>
> This an implementation detailed. It should be transparent for you, don't
> use it.
>
>
>> for that example i posted , i moved the mutex inside the loop and then
>> used a sleep() method for couple of microseconds and got it working ( i
>> mean now both threads seem to work as i expected them).
>> but i want to know if we have sth like , lets say a timed_lock kind of
>> lock !, so that a thread would only hold a mutex for a specified time , and
>> when the timeslice presented in the timed_lock() passes , the
>> aforementioned thread releases the mutex
>>
> and thus other thread(s) can get that mutex and so there would be no need
>> for a sleep() for a thread to wait till it time-slice finishes up and thus
>> releases the mutex .the current timed_lock tries to obtain the mutex in a
>> specified time , which is not the case .
>>
> I think you mixup smth. here. Generally speaking there are critical
> regions in a parallel application. These regions must be protected by
> synchronization objects to grant only a single thread modification for that
> region. Now what you ask for: I know there is a long critical region, but
> in the middle of the critical region I want a break and another thread
> should run than. If it is so, make 2 regions, but there is no way to
> implement smth like that in that simple manner. May be transactions, that
> you interrupt the execution, roll back the calculated state, let others run
> and start the calculation again.
>
>
>> i remember i tried to use yield() for achieving such a possiblity
>> (releasing mutex as soon as possible , i think it kinda worked ,i gave a
>> similare result when i used sleep() )
>>
> How should it help, if the other thread wants in the exact critical
> section which is locked? Yield just gives the remaining CPU time slice of
> the thread to the scheduler. And scheduler might decide who runs next. It
> can even happen, that this one thread runs again, if its prio the highest.
>
>
>
>> here is the code which i wrote to actually speed up the sum action ,
>> which i think didnt give any speed ! would you see where the problem is ?
>> //in the name of GOD
>> //Seyyed Hossein Hasan Pour
>> //Working with Boost::threads
>> #define BOOST_THREAD_USE_LIB
>> #include <iostream>
>> #include <boost/date_time/posix_time/posix_time.hpp>
>>
>> #include <boost/thread.hpp>
>> using namespace std;
>>
>> boost::uint64_t i = 0;
>> boost::uint64_t sum=0;
>> boost::mutex mutex;
>>
>> void IteratorFunc()
>> {
>>
>> for (i ; i<100000; i++)
>> {
>> mutex.lock();
>> sum+=i;
>> cout<<i<<"\t"<<boost::this_thread::get_id()<<endl;
>> mutex.unlock();
>> //boost::this_thread::sleep(boost::posix_time::microseconds(200));
>> boost::this_thread::yield();
>> }
>>
>> }
>>
>> int main()
>> {
>>
>> boost::posix_time::ptime start =
>> boost::posix_time::microsec_clock::local_time();
>> boost::thread thread(IteratorFunc);
>> boost::thread thread2(IteratorFunc);
>>
>> // boost::thread_group threadstore;
>> //
>> // threadstore.add_thread(&thread);
>> // threadstore.add_thread(&thread2);
>> //
>> // BOOST_FOREACH(boost::thread t ,threadstore.threads)
>> // {
>> // cout<<t.get_id();
>> // }
>>
>> boost::posix_time::ptime end =
>> boost::posix_time::microsec_clock::local_time();
>>
>> thread.join();
>> thread2.join();
>>
>> cout << "sum =\t" << sum<< "\t"<<end-start<<endl;
>> return 0;
>> }
>>
> The speed up would rely on the lock-free implementation and dividing of
> work into independent pieces. How sleep suppose to speedup smth. if in that
> time period is nothing calculaded? CPU just stands still. Sum can be
> speedup greatly. The keyword here is work stealing, first proposed in Cilk (
> http://en.wikipedia.org/wiki/Cilk). Intel acquired Cilk. For C++ you can
> use Intel Threading Building Blocks, which has a parallel_reduce algorithm.
> Just download the tutorial:
> http://threadingbuildingblocks.org/uploads/81/91/Latest%20Open%20Source%20Documentation/Tutorial.pdfand take a look at chapter: 3.3.
>
>
>>
>> i also want to know if we have such a capability where i can specify the
>> priority of a thread or a group of thread against the other threads .
>>
> You need to get the native handle and use the native OS functions.
>
>
>> let me explain it little more, by that i mean , suppose we have couple
>> of reader threads and one or two writer threads , is there any kind of
>> possiblity that i can grant the writer thread(s) more priority in terms of
>> accessing
>> a resource (by obtaining the mutex more often ? - or the writer thread(s)
>> deny access to readers in some cases ? ) ? or a part of memory ? ( e.g an
>> array of some kind ? )
>> if it is possible , how can i achieve such possibility ?
>>
> Boost provides basic reader/writer lock concepts. For more finer grained
> concepts I think you will need implement this concept yourself. But usually
> reader/writer is implemented the way that if a writer wants to enter the
> critical section no other readers will enter it before the writer is done.
> And writer has to wait until all currently active readers are done.
> Actually the speedup here would be to increase the priority of readers to
> the priority of the writer.
>
>
>> is it possible that i can know if a thread was successful in doing what
>> it was sent to ?
>>
> Actually, you should decouple threads from work and consider using futures
> and thread pools. You are not interested in the thread's state, but the
> result which was calculated in parallel. So you wait until the result is
> available and verify it.
>
>
>> can i specify that a thread or a group of thread execute in a specific
>> order ? for example thread one must always execute first and thread two
>> must always follow thread one . do we have such a thing ?
>>
> Again, future pattern would help. You put work items in the queue and they
> are calculated in parallel but taken from the queue in a predefined order.
> You can also use a priority queue to sort the items according their
> priority when those are queued. On the other hand: You ask here for
> sequential execution. Why do you need threads than?
>
>
>> do i have any means of talking to threads ? checking the satus of a
>> specific thread ? or group of threads ?
>>
> What status would you like to check?
>
>
>> can i know by any means , that which threads are blocked and which are
>> not ?
>>
> Blocked in terms of what? Waiting to enter the critical section or are
> currently not running?
>
>
>> Thank you so much for your time and please excuse me for such newbish and
>> yet long questions .
>> i really do appreciate your help and time :)
>> Regards
>> Hossein
>>
>>
>>
>> On Wed, Apr 11, 2012 at 7:38 PM, Vicente J. Botet Escriba <
>> vicente.botet_at_[hidden]> wrote:
>>
>>> Le 11/04/12 13:31, Master a écrit :
>>>
>>> Hello all .
>>> i am a newbie to the boost community . i recently started learning about
>>> threads in boost . now there are some questions i would like to ask :
>>>
>>> Welcome.
>>>
>>> 1.where can i find examples showing practical uses of boost::thread
>>> features?
>>>
>>> The documentation doesn't contains too much examples. You can take a
>>> look at the libs/thread/example and tutorial directories :(
>>>
>>> 2.how can i get all threads ID issued by me in my app?
>>>
>>> No direct way other that storing them in a container. What is your use
>>> case?
>>>
>>> 3.how can i iterate through running threads in my app ?
>>>
>>> No direct way other than storing a thread pointer in a container. What
>>> is your use case?
>>>
>>> 4.is there any kind of means to get all the running threads using
>>> boost library? if it does whats the calss? if it doesnt how can i do that?
>>>
>>> See above. I think that you need to specialize the thread class so that
>>> it inserts a handle to the created thread on a container at construction
>>> time and remove it at destruction time.
>>>
>>> 5.can i resume a thread after pausing it ? ( how can i pause a thread?
>>> )
>>>
>>> Boost.Thread doesn't provide fibers or resumable threads. There is
>>> Boost.Fiber for that purpose (not yet in Boost).
>>>
>>> 6. how can i share a variable between two or more threads , suppose i
>>> have a loop , i want two threads to simultaneously iterate through it , if
>>> thread1 counted to 3, thread2 continues it from 4 and so on . ?
>>> i already tried
>>>
>>> You need to protect the access to the loop index variable 'i' with a
>>> mutex as you did with sum.
>>>
>>> HTH,
>>> Vicente
>>>
>>> ------
>>>
>>>> what is wrong with my sample app ?
>>>> #include <iostream>
>>>> #include <boost/thread.hpp>
>>>> using namespace std;
>>>> using namespace boost;
>>>>
>>>> mutex bmutex;
>>>> int i=0;
>>>> int sum=0;
>>>> void IteratorFunc(int threadid)
>>>> {
>>>> for ( ; i<25 ; i++)
>>>> {
>>>> lock_guard<mutex> locker(bmutex);
>>>>
>>>> cout<<"\t"<<threadid<<"\t"<<this_thread::get_id()<<"\t"<<i<<"\n";
>>>> sum+=i;
>>>> }
>>>> }
>>>>
>>>> int main()
>>>> {
>>>> //boost::posix_time::ptime start =
>>>> boost::posix_time::microsec_clock::local_time();
>>>>
>>>> thread thrd(IteratorFunc,1);
>>>> thread thrd2(IteratorFunc,2);
>>>>
>>>> cout<<sum;
>>>> thrd.join();
>>>> thrd2.join();
>>>> }
>>>
>>>
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