Hi,
There's no such thing as a vector (or any other container) of references. Try this and see how the compiler reacts: vector<int &> v;
Jan
Hi all,
I've been trying out boost::any in a messaging system to package up function arguments. A message
call is basically
Message::Call(std::vector<boost::any>& args)
{
try
...a few any_cast<..>
...fire the actual function...
catch
...etc
}
It's all good, except for one niggling problem. Say I have a double-precision value that I need
changed inside the message, so it needs to be passed as a double* or a double& in an argument. The
problem is, if I create a double& inside a boost::any, it doesn't point to the right memory location
once I'm inside the message, and it looks like it's copying the original dereferenced value and
giving me a reference to the copy. If I create a double* inside a boost::any, I get a new pointer
inside the message like the reference, but because the pointer target is correct everything works.
The code looks like this:
...
...
std::vector<boost::any> args;
double d = 1.5;
double* dptr = &d;
msgargs.push_back(dptr);//works fine...
double& dref = d;
msgargs.push_back(dref);//seems to copy d instead of a reference to d...
...
msg->Call(args);
...
I can live with this, I just have to pass "large" objects by pointer so they don't get copied. BUT:
Can anyone tell me why references are creating a copy of the original and not a copy of the
reference, or how I could avoid the copying? Or am I doing something dumb?
Damien
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