Hello Eric,

this code fragment will crash, since 'what' uses iterators into the invalid string

        x::smatch what;
        if(x::regex_match(std::string("      (some_type_ptr) xyz,"), what, regex)) //string goes out of scope after this sentance
        {
            std::cout << what[0] << endl; // boom! string iterators are no longer valid
            std::cout << what[1] << endl;
        }

May be there is a way to probit this kind of behaviour during the compilation or at least this can be stated in the docs...



With Kind Regards,
Ovanes