I checked the maillist history, and there are guys who have the same question with me.

class btQuadWord
{
        protected:
                btScalar m_x;
                btScalar m_y;
                btScalar m_z;
                btScalar m_unusedW;

        public:
                SIMD_FORCE_INLINE const btScalar& getX() const { return m_x; }
};

 class_<btQuadWord>("btQuadWord")
        .def("getX", &btQuadWord::getX)
        ; 
see here: http://lists.boost.org/boost-users/2007/05/27828.php

 

the same question is, when the function return a value which type is not a basic type ( even a pointer ), there will be errors.

 

On 1/14/08, Huang You Gong <huangyougong@gmail.com> wrote:

Hi,

 

I try to use boost.python to invoke C++ library in Python, so I need to expose types and classes.

Here is the c++ head file:

 

typedef int XTYPE;

class XCLASS

{

public:

        XTYPE getvalue( void ){ return XTYPE( 3 ); }

};

       
So I write exposing code in BOOST_PYTHON_MODULE like this:

 

BOOST_PYTHON_MODULE( x )

{

        class_< XCLASS >( "XCLASS" )

                .def( "getvalue", &XCLASS::getvalue, return_value_policy< copy_non_const_reference >() )

        ;

}

 

but there is compiling error as using of undefined type.

what shall I do to make the type XTYPE known by boost.python?

Thanks in advance!

--

Huang You Gong