Robert Ramey wrote:
> Oh, that should be easy:
>
> D1 *d1p;
>
> ar << d1;
> ar >> *d1p;
>
> Robert Ramey

Hi,

At
> ar << d1;
> ar >> bp; // but "bp" points already to an object of type D1

I meant : "bp" is "Base* bp"
So, if I call ar >> *bp; the Base::load will be called, not the derived D1:load.

Actually more precisely, I intend to do so

lass Base {
    ...
    virtual ..
}
class D1 : public Base {
}


Base* bp1 = new D1(..some thing..);
Base* bp2 = new D1(..some thing else..);

ar << *bp1;
ar >> *bp2;

This means for all my serializable classes I have a kind of "=" operator defined.

regards,
Andrei

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