Hi,

In both functions you bind a method of a local object. The local object might die before the thread has a chance to execute that method!
So either you must wait until the thread ends:

void test_boost_thread_1(){

    M p(88);
    boost::thread pthd(boost::bind(&M::m_show, &p));
    pthd.join();

}

or you must bind your object by value - then the copy of the original object will be executed.

Date: Tue, 20 May 2008 21:05:17 +0800
From: hexiay@gmail.com
To: boost-users@lists.boost.org
Subject: [Boost-users] Could two boost threads with the same name run at the same time?

Hi, all，
My code looks like this:

=============================================================

// M is a class, m_show() is one of its methods.

void test_boost_thread_1(){

    M p(88);
    boost::thread pthd(boost::bind(&M::m_show, &p));

}

void test_boost_thread_2(){

    M p(99);
    boost::thread pthd(boost::bind(&M::m_show, &p));

}

===============================================================

"test_boost_thread_1()" and "test_boost_thread_2()" are running at the same time ,but I find that the output is wrong.
If I changed the thread name "pthd" in "test_boost_thread_()" to other name , not "pthd" , it looks ok. why ? ........

Now , many other threads want to run " test_boost_thread_1() " at the "same" time, How could I make it ok ?

Thanks for your time.

Best Regards.

Discover the new Windows Vista Learn more!