On Mon, Jul 28, 2008 at 7:01 PM, Steven Watanabe
<watanabesj@gmail.com> wrote:
AMDG
Marshall Clow wrote:
At 12:00 AM -0500 7/27/08, Meryl Silverburgh wrote:
for (vector<A*>::const_iterator iter = aList.begin() ; iter !=
aList.end(); ++iter) {
A* anA = (*iter);
// break out the for loop if aMethod return true;
if (anA->aMethod()){
break;
}
Isn't this what std::find_if does?
std::find_if is not quite equivalent to the for loop, because std::find_if
is not allowed to modify the input sequence.
Ok, here's myquestion: What does exactly mean that std::find_if is not allowed to change the sequence? How does the code. It is not changing the vector in any way (just using a constant iterator) it is not even modifying the contents of the vector. It is just calling a (possibly not constant) method through a (constant) pointer. To me that is not modifying the input sequence.
Or is it more a general concern that they are not equivalent even if in this case std::find_if could be used?
David