On Fri, Aug 8, 2008 at 10:22 PM, Steven Watanabe <watanabesj@gmail.com> wrote:

AMDG

For example

template<class T>
typename boost::enable_if<boost::is_arithmetic<T>, T>::type foo(const T&);

There is no point to using the lazy versions.

Understood, but how would that be rewritten using lazy versions? It is
more complicated than simply replacing enabe_if with lazy_enable_if?

- Rob.

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