I’ve seen the following:
main(){
...
base *b;
...
ar
& b;
}
But that doesn’t quite help
me. All of our objects come from a memory pool and I either need to know
ahead of time which object to allocate or I need to pass an allocator to the
archive so that it can get the memory from the pool.
Are either of these possible? Also,
in the above example, how does the archive allocate the memory for ‘b’?
Does it use new? Or does it have it’s own pre-allocated store?
Thanks,
Ryan
From: boost-users-bounces@lists.boost.org
[mailto:boost-users-bounces@lists.boost.org] On Behalf Of Robert Ramey
Sent: 04 March 2009 17:30
To: boost-users@lists.boost.org
Subject: Re: [Boost-users] [Serialization] Load an object from the base
pointer
This
is explained in the documentation and illustrated by the demos and tests.
In
fact, you can even build a progam which will be able to de-serialize types
included
in
DLLS which have yet to be created.
Hi,
How can I read in a from a stream when I
don’t know the exact type I will be getting? All objects I receive
will derive from the same base class, but I won’t know when I receive the
stream what the derived type will be and therefore I can’t create it in
advance (like in the docs).
class base
{
…
}
class derived1 : public base
{
…
}
class derived2 : public base
{
…
}
int main()
{
// Get a stream from
somewhere
boost::archive::binary_iarchive ia( instream );
base b0;
derived1 d1;
derived2 d2;
is >> // derived1
or derived2???
}
Ryan Fowler
Software Engineer
Thomson Reuters
Phone: +442075427063
ryan.fowler@thomsonreuters.com
thomsonreuters.com
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