Yeah.. exactly this is what I wanted to know..

thank you.

2009/8/10 Björn Karlsson <Bjorn.Karlsson@readsoft.com>
Hello R.P,

Inheriting from enable_shared_from_this more than once is not a good idea.

> From: boost-users-bounces@lists.boost.org [mailto:boost-users-
> bounces@lists.boost.org] On Behalf Of R. P. Janaka
> Sent: Monday, August 10, 2009 6:54 AM
> To: boost-users@lists.boost.org
> Subject: Re: [Boost-users] How shared_from_this() work when it
> inherited from more than one time
>
> But in my case there is no option like this (Class A is a base library
> class). So I have to do this.
>

Don't let B inherit from enable_shared_from_this. You've already done that in A. So your question then becomes "how do I retrieve a shared_ptr<B> from this?". Here's how:

 boost::shared_dynamic_cast<B, A>(shared_from_this());

In the example you've provided, it would also be safe to use boost::shared_static_cast.
To conclude: You should only inherit from enable_shared_from_this in A, and B should only inherit from A.

> I did the above to avoid the ambiguous call error So how can I specify
> that i am calling the shared_from_this() in class B....?

You did. But the problem is that you have two weak_ptrs -- one weak_ptr<A> and one weak_ptr<B> -- and only one of them will be initialized correctly when you create the smart pointer. (If you're interested in debugging your case to really understand what happens, have a look at the function
sp_enable_shared_from_this() in shared_ptr.hpp.)

Does that help?

Cheers,
Bjorn Karlsson

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--
Regards,
R. P. Janaka