Rutger,

I didn't know it would exit when it ran out of work. Your solution worked perfectly! I added that line and Service.run() no longer exits prematurely. Thanks for your insight!

-- Dylan

For anyone who might try to do something similar in the future, here is the complete code listing that works properly.

#include <iostream>
#include <boost/asio.hpp>
#include <boost/thread/thread.hpp>
using namespace std;

boost::asio::io_service Service;

void OnSignal()
{
    cout << "Got timing signal" << endl;
}

void TimingSignalThread()
{
    boost::this_thread::disable_interruption di;
    while(!boost::this_thread::interruption_requested())
    {
        boost::this_thread::sleep(boost::posix_time::millisec(500));
        Service.post(&OnSignal);
    }
}

void ServiceRunner()
{
    boost::asio::io_service::work RunForever(Service);
    Service.run();
}

int main()
{
    boost::thread TimingThread(&TimingSignalThread);
    boost::thread ServiceThread(&ServiceRunner);
    cin.get();
    TimingThread.interrupt();
    TimingThread.join();
    Service.stop();
    ServiceThread.join();
    cout << "Joined all threads." << endl;
    return 0;
}

On Wed, Oct 28, 2009 at 4:42 PM, Rutger ter Borg <rutger@terborg.net> wrote:

Dylan Klomparens wrote:

> My question is, why does my call to Service.post always fail? I know it is
> failing because the function that I post never gets called. There is not
> explicit return code or thrown exception to indicate that there is a
> problem.
>

An io_service keeps running as long as it has work to do. You can force an
io_service to keep running by attaching a work object. Try adding

boost::asio::io_service::work work(Service);

just below main, before the call to Service.run().

Cheers,

Rutger

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