Hi all,<div>i&#39;m trying to wrap c++ functions that have pointer variables. The test example i&#39;m using is shown below:</div><div><div>int World::addition(int* a, int* b)</div><div>{</div><div><span class="Apple-tab-span" style="white-space:pre">	</span>int z = *a + *b;</div>
<div><span class="Apple-tab-span" style="white-space:pre">	</span>return z;</div><div>}</div><div><br></div><div>Now, i defined it in my wrapper as :</div><div>.def(&quot;addition&quot;, &amp;World::addition)</div><div><br>
</div><div>My code compiles, but when I try to execute it from python, i get this error:</div><div>Python Argument types in World.Addition(World, int, int) did not match C++ signature: addition(class World {lvalue}, int* , int*)</div>
<div><br></div><div>The problem is, how to get hold of a pointer in python? Or is there a workaround to define the function differently in the wrapper file?</div><div><br></div>-- <br>Regards,<br>Hitesh Dhiman<br>Electrical Engineering<br>
National University of Singapore<br>
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