Marco Meoni - Sbaush wrote:
> Yes.
> I did an example like this to learn how to serialize in the
> "classical" way.
>
>
> My problem is that i can't define a serialize method inside
> Container, but i would serialize it anyway. How can i serialize the
> Example strut entirely? 
>
>
> Do you understand my problem?
>
>
> On Fri, Apr 30, 2010 at 3:49 AM, Robert Ramey <ramey@rrsd.com> wrote:
>
> Marco Meoni - Sbaush wrote:
>> Can someone help me?
>> Robert, where can I find what you're talking about?
>
> I don't know what you're trying to do so I'll take a guess.
>
> Does this look like what you want to do?
>
> struct Container {
>     int m_container_member;
>     ... // more members
>     template<class Archive>
>     void serialize(Archive & ar, const unsigned int version){
>         ar & m_container_member;
>         ... // more members
>     }
> };
>
> struct Example {
>     friend class boost::serialization::access; // not really
> necessary as all "struct" members are public
>     template<class Archive>
>     void serialize(Archive & ar, const unsigned int version){
>         ar & m_container;
>     }
> };
>
> int main(int argc, char * argv[]){
>     const Container c = ...
>     std::fostream os("filename");
>     boost::serialization::archive ar(os);
>     ar & c;
> }
>
> Does that help any?
>
> Robert Ramey
>
>
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