> You are entirely correct. The reverse function is missing the const overload,
and this will cause a problem when returning a temporary to a constant range
that has mutable elements. A workaround, which I expect you have already thought
of, would be to hold a const reference to the range in a variable and pass this
into reverse.I shall put a correction into the trunk as soon as possible. I
shall also review all of the algorithm functions for similar mistakes.I
apologize for my oversight and for any inconvenience this has caused.