Thanks, Nate. Instead of writing "const std::string& separator", I wrote "std::string separator" - missed this somehow. can't believe it. Thank you, again.
The following code compiles fine with MSVC10 and gcc:
> Hi,
>
> Here is a piece of code that _only_ works when I provide it a
> hard-coded constant ";":
>
> typedef boost::char_separator<char_type_t> sep_type_t;
> typedef boost::tokenizer<sep_type_t> tokenizer_t;
>
> sep_(pa_->separator_.c_str()),
> t_(messageString,sep_),
> i_(t_.begin())
>
> It wouldn't work with the separator passed in a variable
> (pa_->separator.c_str()). Tokenizer wouldn't work even if I initialize
> a const char* with a ";" and then pass that const char *variable to
> sep_ above. It gives me the following errors on if I pass separator in
> a variable:
>
> error C2780: 'bool
> boost::char_separator<Char>::operator ()(InputIterator
> &,InputIterator,Token &)' : expects 3 arguments - 1 provided
>
> Any idea how I can pass it a separator in a variable?
#include <boost/tokenizer.hpp>
template <typename char_type_t>
struct S
{S(const std::string& messageString, const std::string& separator)
typedef boost::char_separator<char_type_t> sep_type_t;
typedef boost::tokenizer<sep_type_t> tokenizer_t;
: sep_(separator.c_str()),
t_(messageString, sep_),
i_(t_.begin()) {}
sep_type_t sep_;
tokenizer_t t_;
typename tokenizer_t::iterator i_;
};
int main()
{
S<char> s("foo bar", " ");
}