Hi All<div><br></div><div>This doesn&#39;t work.</div><div><br clear="all"><div><div><font class="Apple-style-span" face="&#39;courier new&#39;, monospace">template&lt;typename T&gt; struct S</font></div><div><font class="Apple-style-span" face="&#39;courier new&#39;, monospace">{</font></div>

<div><font class="Apple-style-span" face="&#39;courier new&#39;, monospace">    typename disable_if&lt;is_const&lt;T&gt;, int&gt;::type mutating_method();</font></div><div><font class="Apple-style-span" face="&#39;courier new&#39;, monospace">}</font>;</div>

</div><div><br></div><div>I understand why not, although only after the compiler threw it out, but obviously (in hindsight),</div><div>the method itself is not a template, so can&#39;t be selectively instantiated.</div><div>

<br></div><div>The question is whether and how I can achieve the effect I&#39;m after, ie., that the method</div><div>is not present if the struct is instantiated with a const type?</div><div><br></div><div>Thx, Rob.</div>

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