On Mon, Oct 10, 2011 at 3:01 AM, <Viatcheslav.Sysoltsev@h-d-gmbh.de> wrote:
On Sun, 09 Oct 2011 19:04:39 +0200, Matwey V. Kornilov <matwey.kornilov@gmail.com> wrote:

and, actually let a=b=x,

lim_{x->0} ((x-x)/min(|x|,|x|)) = lim_{x->0} (0/min(|x|,|x|)) = lim_{x->0} (0) = 0


I'am not active mathematician, but I believe lim {x->0} (0/x) is 0/0 and thus considered undefined, not 0.

I haven't run the numbers either, but 0/0 is indeed undefined or Single.NaN if you prefer.
 
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