Hello John,

sorry, I made a copy/paste mistake. The lines should be as followed:

FALSE:
std::string data = "Today is the 2012-01-31";
std::string replace = "\\5\\g{sep}\\4\\g{sep}\\1\\2";
std::string pattern = "(19|20)(\\d\\d)(?<sep>[- /.])(0[1-9]|1[012])\\g{sep}(0[1-9]|[12][0-9]|3[01])";
boost::regex rx(pattern);

std::string replaced = boost::regex_replace(data, rx, replace);

RESULT: "Today is the 31g{sep}01g{sep}2012"

If I use numbers instead of named groups as followed it works:

CORRECT:
std::string data = "Today is the 2012-01-31";
std::string replace = "\\5\\3\\4\\3\\1\\2";
std::string pattern = "(19|20)(\\d\\d)([- /.])(0[1-9]|1[012])\\3(0[1-9]|[12][0-9]|3[01])";
boost::regex rx(pattern);

std::string replaced = boost::regex_replace(data, rx, replace);

RESULT: "Today is the 31-01-2012"

Best Regards
NoRulez


Am 31. Jan 2012 um 09:41 schrieb John Maddock <boost.regex@virgin.net>:

> does boost's regex_replace not recognize named captures/groups or did I
> something wrong?

Yes it does, but remember that the C++ compiler gobbles up the \'s before
regex gets to se those strings, so use \\ everywhere and you should be fine.

HTH, John.

> std::string date = "2012/01/30";
> std::string replace = "\5\g{separator}\4\g{separator}\1\2"; // should be
> => 30/01/2012
> boost::regex
> rx("^(19|20)(\d\d)(?<separator>[/.])(0[1-9]|1[012])\g{separator}(0[1-9]|[12][0-9]|3[01])$");
>
> std::string replaced = boost::regex_replace(date, rx, replace);
>
> The content in "replaced" is now "30\g{separator}01\g{separator}2012"
>
> Thanks in advance
>
> Best Regards
> NoRulez
> _______________________________________________
> Boost-users mailing list
> Boost-users@lists.boost.org
> http://lists.boost.org/mailman/listinfo.cgi/boost-users

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