2013/11/8 Rahul Mathur <srivmuk@gmail.com>

On Fri, Nov 8, 2013 at 11:49 AM, Igor R <boost.lists@gmail.com> wrote:

> I have a string Timestamp of 1383889129 which on ONLINE conversion from
> string to hex gives a 10 bytes as "31 33 38 33 38 38 39 31 32 39".

The above is not "conversion from string to hex", but merely a hex
representation of every ascii character in "1383889129" string.

> But, the need is to have the TIMEStamp in 8 bytes only.

It's unclear what you want exactly. If you need a time-stamp as a
number, use boost::lexical_cast<int>("1383889129") or any other
ascii-to-int conversion.

> YES, do have the TIMESTAMP from string viz 1383889129. Since, the declaration of TIMESTAMP is "char TIMESTAMP[8]", so looking how to convert this?

狢 think you didn't provide enough information, so different solutions can give different answers. Perhaps you don't have enough information or it's up to you to choose?

1383889129 looks like a decimal it. You say you get it as a string. You can convert it to a 32-bit int like this:

string s = "1383889129";

uint32_t i = boost::lexical_cast<uint32_t>(s); // you probably can use plain old unsigned int if it has 32 bits

Now you can put this int's hex representation into an array of 8 bytes. I assume each byte is supposed to contain a character representing a hexadecimal digit [0-9a-f]. Here it is left unspecified, if ts[0] should be the least or most significant digit.

Here's what you can do (ts[0] will be the most significant digit; warning: not tested, I'm not sure if I named the manipulators right, but I hope you'll get the idea):

TIMESTAMP ts;

ostringstream os;

os << hex << setfill('0') << setw(8) << i;

boost::copy( os.str(), ts ); // copy from Boost.Range

HTH,

Kris