Classification: Honeywell Internal

All serialize methods (except the base class serialize method) have as their first three lines code like this (with the appropriate

 BOOST_LOG_TRIVIAL(trace) << CLASS_METHOD << "  called";
   boost::serialization::void_cast_register<derived, base>(
 static_cast<derived *>(nullptr),
 static_cast<base *>(nullptr)
      ); 
 ar & BOOST_SERIALIZATION_BASE_OBJECT_NVP(base);

If that’s what you’re referring to, it didn’t fix the problem

---

Steve H.

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This message classified as Honeywell Internal by Hickman, Steve (AdvTech) on Tuesday, June 03, 2014 at 3:34:21 AM.
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From: Robert Ramey [mailto:robertmacleranramey@gmail.com]
Sent: Sunday, June 01, 2014 11:22 AM
To: boostusers@googlegroups.com
Cc: robertmacleranramey@gmail.com; boost-users@lists.boost.org; Hickman, Steve (AdvTech)
Subject: Re: [Boost-users] [serialization] deserialized instance empty even though proper serialize methods called

On Saturday, May 31, 2014 2:50:35 PM UTC-7, Robert Ramey wrote:

I woke up in the middle of the night.

The "registration" base/derived pair is a side effect of 

class Base {

    virtual~Base();

    template<class Archive);

    void serialize(Archive ar, const unsigned int version);

};

class Derived {

    virtual~Derived();

    template<class Archive);

    void serialize(Archive ar, const unsigned int version);

};

template<class Archive);

void Derived::serialize(Archive ar, const unsigned int version){

   ar & boost::serialization::base_object<Base &>( *this);   // side effect void_cast_register(Base, Derived) which updates the table when DLL is loaded

}

So I'm guessing that you're not calling the base class serialization so the Base/Derived pair isn't being registered.

Solution:

explicitly declare, define and call the Base class serialization even though it is empty.

or

explicitly invoke register void_cast::register base/derived - i forget the exact name.

I'll be surprised if that doesn't solve your problem.

RObert Ramey