LSAny hint is very much appreciated.Is this the expected behavior or am I still doing something wrong. Of course, if not signal is set I want the program to finish the loop and exit normally.Thanks for the quick response. Now the consecutive signals are handled correctly and it behaves as I wanted when sending SIGINT signals.However, and this also holds for my original example (which I only noticed now), if I don't ever send SIGINT the program never terminates even if I set the number of loop iterations to a very small number (e.g. 10). If I stop the program in the debugger after some time it still hasn't exited the call to io.run().
On Wed, Aug 27, 2014 at 11:04 PM, niXman <i.nixman@autistici.org> wrote:
Lutz Schneider 2014-08-28 00:11:Hi,
Hi,
I have a program and would like to stop it by sending SIGINT for writing
some data to a file instead of exiting immediately. However, if the user of
the program sends SIGINT again then the program should quit immediately and
forget about writing data to a file. For portability reason I would like to
use boost::asio for this purpose.
My initial (simplified) approach (see below) did not work. Is this not
possible or am I missing something?
handler seems to be called only once (printing out the message) and the
program always stops when the loop has reached the max iteration number.
void handler(
const boost::system::error_code& error,
int signal_number)
{
if (!error)
{
static bool first = true;
if(first){
std::cout << " A signal(SIGINT) occurred." << std::endl;
// do something like writing data to a file
first = false;
}else{
std::cout << " A signal(SIGINT) occurred, exiting...." << std::endl;
exit(0);
}
}
}
int main(){
// Construct a signal set registered for process termination.
boost::asio::io_service io;
boost::asio::signal_set signals(io, SIGINT);
// Start an asynchronous wait for one of the signals to occur.
signals.async_wait(handler);
io.run();
size_t i;
for(i=0;i<std::numeric_limits<size_t>::max();++i){
// time stepping loop, do some computations
}
std::cout << i << std::endl;
return 0;
}
You should set async waiting for next signal immediately in handler, like this:
#include <iostream>
#include <boost/bind.hpp>
#include <boost/ref.hpp>
#include <boost/asio.hpp>
void handler(
boost::asio::signal_set &sset,sset.async_wait(
const boost::system::error_code& error,
int signal_number)
{
if (!error)
{
boost::bind(
handler
,boost::ref(sset)
,boost::asio::placeholders::error
,boost::asio::placeholders::signal_number
)
);boost::bind(
static bool first = true;
if(first){
std::cout << " A signal(SIGINT) occurred." << std::endl;
// do something like writing data to a file
first = false;
}else{
std::cout << " A signal(SIGINT) occurred, exiting...." << std::endl;
exit(0);
}
}
}
int main(){
// Construct a signal set registered for process termination.
boost::asio::io_service io;
boost::asio::signal_set signals(io, SIGINT);
// Start an asynchronous wait for one of the signals to occur.
signals.async_wait(
handler
,boost::ref(signals)
,boost::asio::placeholders::error
,boost::asio::placeholders::signal_number
)(http://pastebin.com/RuxQ5ARw)
);
io.run();
size_t i;
for(i=0;i<std::numeric_limits<size_t>::max();++i){
// time stepping loop, do some computations
}
std::cout << i << std::endl;
return 0;
}
--
Regards, niXman
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