Ah, ok.

I assumed the syntax

ar & c.special_member; //uses it's own version

only worked with the intrusive version (i.e. serialize as a member of MemberClass).

Seems it still works with non-intrusive. Pure magic.

Thanks!

On Mon, Mar 5, 2018 at 6:31 PM, Robert Ramey via Boost-users <boost-users@lists.boost.org> wrote:

On 3/5/18 9:06 AM, Lars Ruoff via Boost-users wrote:

Sorry, still don't understand.
As said, i have defined
void serialize(Archive & ar, MemberClass & m, const unsigned int version);

so
template<class Archive>
void serialize(Archive & ar, ContainerClass & c, const unsigned int version)
{
ar & c.other_members; // easy - built-in type
serialize(ar, c.special_member, version); //use same version???
}
compiles.

where is

template<class Archive>
void serialize(Archive & ar, special_member_type & t, const unsigned int version){
ar & ??;
};

?

If you have this you could write:

template<class Archive>
void serialize(Archive & ar, ContainerClass & c, const unsigned int version){
ar & c.other_members; // easy - built-in type
ar & c.special_member; //uses it's own version
}

Robert Ramey

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