Adam Wulkiewicz wrote On 26-11-2014 21:25:
Of course in all formulas some approximation of a globe is used. My assessment is based on a fact that SSF assume thet a globe is a sphere
Ah, so you did not read my blog, and apparently also not my statements that SSF can be used on a spheroid.
So I repeat it again, there it goes:
http://barendgehrels.blogspot.nl/2011/06/spherical-side-formula.html
Quoting, a.o.:
"Summary: Using some high-school mathematics I presented an algorithm and a formula to calculate at which side a point is with resepect to a segment, on a sphere or on the Earth"
Beside the summary, it has a whole paragraph about the Ellipsoid.
Because this is exact, and Vincenty is an approximation (close to reality, but still, an approximation), I now just assume that these results are correct and the Vincenty approximation is off within ranges of 0.6.
I assume that, until it is proven that it is the other way round...
If SSF was only applicable for 100% spheres, the error would be much larger. Compare Haversine/Vincenty, it can be off many kilometers.
Note: it is different from distance, where an exact mathematical formula for ellips or spheroid just does not exist.
and Vincenty that it's a spheroid. So the approximation is closer to reality. And the greater the flattening, the greater the difference between SSF and Vincenty. I'm not considering precision, numerical errors, stability etc.
As for the Vincenty formula here: http://www.icsm.gov.au/gda/gdav2.3.pdf states:
"Vincenty's formulae (Vincenty, 1975) may be used for lines ranging from a few cm to nearly 20,000 km, with millimetre accuracy."
Calculation done with SSF is probably also precise but it uses a sphere model, that's all.
Nope.