Proto grammars and transforms handle this better than evaluators, which are deprecated. It would pay to look into some examples that use transforms. Sorry, that's all the advice I have time for at the moment.
\e
I'd try to use IsVector.
I'm not sure how to do this with a grammar (maybe someone can pitch in) but you could do something like this
enable_if< IsVector<typename proto::result_of::value<Expr>::type> >On 14 April 2016 at 18:04, Frank Winter <fwinter@jlab.org> wrote:I made some progress. If I specialize struct VectorSubscriptCtx::eval with Vector10, like
struct VectorSubscriptCtx
{
VectorSubscriptCtx(std::size_t i) : i_(i) {}
template<typename Expr, typename EnableIf = void>
struct eval
: proto::default_eval<Expr, VectorSubscriptCtx const>
{};
template<typename Expr>
struct eval<
Expr
, typename boost::enable_if<
proto::matches<Expr, proto::terminal< Vector10 > >
>::type
>
{
//..
}
};
then it works (is was specialized with Vector). It also works when using the Boost _ literal (match anything), like
template<typename Expr>
struct eval<
Expr
, typename boost::enable_if<
proto::matches<Expr, proto::terminal< _ > >
>::type
However, I feel this is not good style. Can this be expressed with the is_base_of trait instead?
On 04/14/2016 10:10 AM, Mathias Gaunard wrote:
On 14 April 2016 at 14:43, Frank Winter <fwinter@jlab.org
<mailto:fwinter@jlab.org>> wrote:
Hi all!
Suppose you'd want to implement a simple EDSL (Embedded Domain
Specific Language) with Boost.proto with the following requirements:
Custom class 'Vector' as terminal
Classes derived from 'Vector' are working terminals too, e.g.
Vector10
[...]
template<typename T>
struct IsVector
: mpl::false_
{};
template<>
struct IsVector< Vector >
: mpl::true_
{};
Surely this should be true for all types derived from Vector.
template<typename T, typename Enable = void>
struct IsVector
: mpl::false_
{};
template<typename T>
struct IsVector<T, typanem enable_if< is_base_of<Vector, T> >::type>
: mpl::true_
{};
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