[boost] Re: shared_ptr: operator<

From: Joe Gottman (joegottman_at_[hidden])
Date: 2000-02-27 20:22:38

----- Original Message -----
From: Braden N. McDaniel <braden_at_[hidden]>
To: <boost_at_[hidden]>
Sent: Sunday, February 27, 2000 6:47 PM
Subject: [boost] Re: shared_ptr: operator<

> On Sun, 27 Feb 2000, Kevlin Henney wrote:
>
> > "For templates greater, less, greater_equal, and less_equal, the
> > specializations for any pointer type yield a total order, even if the
> > built-in operators <, >, <=, >= do not." [20.3.3 para 8]
>
> Okay, silly question time: What exactly is meant here by the term "total
> order"?
>
> --

    An ordering relation such that for every pair of elements x and y,
exactly one of the following statements is true: x < y, x == y, x > y.