Re: [boost] new version of array<>

From: Valentin Bonnard (Bonnard.V_at_[hidden])
Date: 2000-08-01 11:30:16

Mark Rodgers wrote:

> Is there anything wrong with
> 
>      template <typename T2>
>      array &operator=(const array<T2,N> &rhs) {
>         std::copy(rhs.begin(),rhs.end(), begin());
>         return *this;
>      }
> 
> This works for me.  Of course, because rhs may be of a
> different type,

If operator= is called with the operator syntax (a = b), 
then types _must_ be differents.

-- 
Valentin Bonnard