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From: Bill Wade (bill.wade_at_[hidden])
Date: 2000-08-31 12:55:11

> From: William Kempf [mailto:sirwillard_at_[hidden]]

> --- In boost_at_[hidden], "Bill Wade" <bill.wade_at_s...> wrote:

> > I'm not sure I know how to do a safe read with just
> > InterlockedExchange.

> int b = a; // according to what you posted, this is atomic

Right. On win32 'a' is read atomically and 'b' hasn't yet been shared.

> InterlockedExchange(&b, a); // equivalent to above

True. In particular if a plain old read is not atomic the second version
doesn't atomically read a value from a. The second argument to
InterlockedExchange is passed by value, so

  c = InterlockedExchange(&b,a);

is semantically equivalent to

  tmp = a;


  c = tmp;

> Regardless, I don't *think* you'll find a performance
> difference with this and InterlockedExchange. It surely won't be a
> 3x difference.

The output from the following program on my machine (just one thread) is
so it is just a 2.705x difference, with loop overhead thrown in.

#include <iostream>
#include <time.h>
#include <vector>
#include <windows.h>

using namespace std;

int main()
  const int size = 10000000;

  vector<long> v(size);

  long i;
  long* base = &v[0];
  long sum = 0;

  // Get a time for plain old read.
  clock_t t = clock();
  for(i = 0; i < size; ++i)
    sum += base[i];
  t = clock() - t;
  cout << t << endl;

  // Get a time for the "identical" code using interlocked exchange
  long temp;
  t = clock();
  for(i = 0; i < size; ++i)
    sum += (InterlockedExchange(&temp, base[i]), temp);
  t = clock() - t;
  cout << t <<endl;

  return sum;

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