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From: Greg Colvin (gcolvin_at_[hidden])
Date: 2001-05-16 10:53:17


From: Beman Dawes <bdawes_at_[hidden]>
> At 03:29 AM 5/16/2001, Thomas Maeder wrote:
>
> >This problem report is a result of a discussion in
> >news://newsgroups.borland.com/borland.public.cppbuilder.language
> >
> >The following program demonstrates it, using boost 1.21.1 and gcc 2.95.3:
> >
> >#include <iostream>
> >
> >#include "boost/smart_ptr.hpp"
> >
> >struct S
> >{
> > ~S()
> > {
> > std::cout << "~S()\n";
> > }
> >
> > boost::shared_ptr<S> next;
> >};
> >
> >int main()
> >{
> > boost::shared_ptr<S> head(new S);
> > head->next.reset(new S);
> > std::cout << "before assignment\n";
> > head = head->next;
> > std::cout << "after assignment\n";
> >}
> >
> >The output is
> >
> >before assginment
> >~S()
> >~S()
> >after assginment
>
> Ouch!

Amen.

> >while one would expect it to be
> >
> >before assignment
> >~S()
> >after assignment
> >~S()
> >
> >The reason is that the shared_ptr copy-assignment operator first reduces
> >the reference count of the previously owned object and only then
> increases
> >that of the newly owned object; if both objects are the same, strange
> >things happen.
>
> It isn't really a case of both objects being the same, but that the right
> hand object is transitively dependent on the left hand object.
>
> The code causing the problem is:
>
> void share(T* rpx, long* rpn) {
> if (pn != rpn) { // Q: why not px != rpx? A: fails when both == 0
> dispose();
> px = rpx;
> ++*(pn = rpn);
> }
>
> My first reaction is to change it to:
>
> void share(T* rpx, long* rpn) {
> if (pn != rpn) { // Q: why not px != rpx? A: fails when both == 0
> ++*rpn; // done before dispose() in case rpn transitively
> // dependent on *this (bug reported by Thomas Maeder)
> dispose();
> px = rpx;
> pn = rpn;
> }

This looks right to me.

 
> I'll have give it a bit more thought. Greg? Also do some testing. The
> test program needs updating anyhow.
>
> Thanks for the bug report.
>
> --Beman
>
>
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