Re: [boost] function and BOOST_NO_DEPENDENT_BASE_LOOKUP

From: Brad King (brad.king_at_[hidden])
Date: 2001-06-27 11:07:19

> Consider this little tidbit of overload resolution:
> 
> struct Foo {
>   template<typename T> Foo& operator=(const T&);
> };
> 
> struct Bar : public Foo {
>   template<typename T> Bar(T);
>   Bar& operator=(const Bar& other);
> };
> 
> Bar b;
> b = 5;
> 
> So what happens at b=5? Clearly the candidates are either:
> 1) a call to Foo::operator=(T). This requires:
> 2) a call to Bar::operator=(const Bar&)
I believe that Foo::operator= will never be considered because its name is
hidden by Bar::operator=.

-Brad