
Boost : 
From: garfaus_at_[hidden]
Date: 20010929 06:25:06
> The code below seems like it must treat a conversion from A to B
the same
> way as a conversion from B to A (since the expression true ? : A
() : B() has
> the same type as true ? : B() : A()). Is that intended?
>
The intention is to do the usual arithmetic conversions
as explained in clause 5 (5/9), to bring types A and B
to a common type.
 Gabriel
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