Re: Boost.Python question

From: MikeEnsor_at_[hidden]
Date: 2001-11-08 14:03:16

I'm looking for a conversion from my own type to Python.  I created a 
class called "Instance".  I need to return that type back to Python.  
It is wrapped with boost as a class.  The line I use (it isn't 
working) is:
PyObject* GetInstance(MyList& l)
{
   Instance i;
   l.GetInstance(i); // pass by ref, not my code that does this
   return boost::python::to_python(i);
}

I do have Instance wrapped and included into the module, but I can not 
return it back like this.  The compiler says that Instance is not one 
of the converted types.  I can return the "super" type (Instance is 
derived from InstBase), and that works, but it does not have the 
specific info I need from Instance.  Does this clear things up more?  
Thank you very much for helping me out.

Mike 

--- In boost_at_y..., "David Abrahams" <david.abrahams_at_r...> wrote:
> Hi Mike,
> 
> Sorry, I'm a bit lost. There is a to_python(PyObject*) declaration 
in
> boost/python/conversions.hpp. Is that not what you're looking for?
> 
> -Dave
> 
> ----- Original Message -----
> From: <MikeEnsor_at_C...>
> To: <boost_at_y...>
> Sent: Thursday, November 08, 2001 1:41 PM
> Subject: [boost] Boost.Python question
> 
> 
> > I am trying to return an already wrapped c++ object from a 
function.
> > The way I have it set is that I return a PyObject* which is 
created
> > depending on the input and various other functions.  I have no 
problem
> > creating binary, string, double, and int values and returning them 
as
> > a PyObject*.  However, I can not figure out how to return a 
reference
> > (copied or reference) back to Python via PyObject.  When I try to
> > return using boost::python::to_python(obj) the compiler says that
> > there is not a converstion.  I have included it in the module, but 
do
> > I have to create a "to_python"?  Where do I find details on how to 
do
> > that?  Thank you,
> > Mike Ensor
> >
> >
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